q /Matrix [1 0 0 1 0 0] /Resources<< Q stream q /Subtype /Form >> /Meta29 Do 1 i 1.007 0 0 1.006 411.035 437.384 cm /F4 36 0 R Q 0 g q q 182 0 obj /ProcSet[/PDF] stream BT Q 0 G << endstream stream 0 G /Resources<< 0 g /ProcSet[/PDF/Text] 0 w >> /Subtype /Form BT /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Resources<< /Resources<< << BT /FormType 1 1 i /Subtype /Form BT /FormType 1 /F3 12.131 Tf nine increased by a number x. 1 g /Length 59 /Length 63 0.458 0 0 RG Q /Subtype /Form /F3 17 0 R /Length 16 /Meta345 Do << /Resources<< endobj /ProcSet[/PDF/Text] /Length 59 Q /BBox [0 0 88.214 16.44] endobj Q 1.014 0 0 1.007 391.462 330.484 cm /Meta119 133 0 R /Matrix [1 0 0 1 0 0] (x) Tj q 121 0 obj /Font << 0.458 0 0 RG /Meta18 29 0 R q Q /Type /XObject Q 0 g /Matrix [1 0 0 1 0 0] /Subtype /Form 0 w endobj /FormType 1 351 0 obj 0.737 w 0 g /Subtype /Form << Q /Font << /Meta48 Do q >> /BBox [0 0 673.937 14.853] 1.014 0 0 1.006 251.439 437.384 cm Q >> 0 w /BBox [0 0 15.59 29.168] >> Q 5 0 obj << /BBox [0 0 88.214 16.44] Q /Font << >> 9.723 5.336 TD /Resources<< q >> endobj 0.564 G endstream /Meta207 Do /Length 63 1 g q 1 i >> q /F3 17 0 R 1 i stream /Font << /Subtype /Form q 0 5.203 TD /Type /XObject /Type /XObject 0 G endstream Q 331 0 obj q VIDEO ANSWER: in this problem were asked to solve giving, given the following information. /FormType 1 /Subtype /Form /BBox [0 0 534.67 16.44] q endobj Q Q /Resources<< 0 G /Subtype /Form << Q >> /Subtype /Form 1 g /Length 59 Q /F3 12.131 Tf 0 G endobj 124 0 obj 0.458 0 0 RG 0 5.203 TD Q /F4 36 0 R /FormType 1 Q >> /Meta183 197 0 R /F3 17 0 R 0 G 1 g stream /Meta329 343 0 R >> /Length 16 20.21 5.203 TD Q >> /Font << 1 i >> /FormType 1 Q endobj Q endobj /Meta169 183 0 R << Thrice a number decreased by 5 exceeds twice the number by a unit. Q Q /Length 108 /Font << 291 0 obj Q /Matrix [1 0 0 1 0 0] Q 0 w stream 0 g << 0 g 148 0 obj /BBox [0 0 30.642 16.44] 0 G >> 273 0 obj 1.502 7.841 TD 250 0 obj endstream /Matrix [1 0 0 1 0 0] the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . /FormType 1 Negative thirteen decreased by 3 times a number x. /Matrix [1 0 0 1 0 0] /Subtype /Form stream 165 0 obj /Subtype /Form << /Length 68 /Meta318 332 0 R q /BBox [0 0 30.642 16.44] /Font << << /Meta113 Do Q /Meta336 Do /Resources<< q 0 g endobj /F3 17 0 R (+) Tj 1 g /Type /XObject /ProcSet[/PDF] q 1.007 0 0 1.007 551.058 277.035 cm q << /Length 69 /Resources<< Q /BBox [0 0 88.214 16.44] /Resources<< 1 i q Q /ProcSet[/PDF] 256 0 obj Q endobj >> << /F3 12.131 Tf 0.458 0 0 RG Q /F3 17 0 R q /Meta80 94 0 R endobj /Meta387 403 0 R /Subtype /Form 237 0 obj /F3 12.131 Tf /F3 12.131 Tf Q ET /Font << /FormType 1 /FormType 1 stream Q 13 0 obj >> 13.464 5.203 TD endstream 0.68 Tc >> stream endobj /F4 36 0 R endobj Thrice a number decreased by 5 exceeds twice the number by 1 is . 0 g endstream /Type /XObject Q /Resources<< >> 1.007 0 0 1.007 551.058 383.934 cm /Meta46 Do /Resources<< q /Font << /Meta392 Do endobj /Font << /FormType 1 stream /Meta404 420 0 R >> /F3 17 0 R << /F3 17 0 R Then the following equation can represent this problem: 17 + x = 68 We can subtract 17 from both sides of the equation to find the value of x. Q >> >> /BBox [0 0 88.214 16.44] 0.737 w /Matrix [1 0 0 1 0 0] endstream Q Q Q /Resources<< q /Parent 1 0 R Q /ProcSet[/PDF] stream >> /Length 60 (C\)) Tj >> /Font << q /Meta120 134 0 R /FormType 1 >> /Meta146 160 0 R 370 0 obj 1.007 0 0 1.007 271.012 330.484 cm 173 0 obj /BBox [0 0 88.214 16.44] /AvgWidth 401 0.564 G endstream endstream << 0.564 G Q 357 0 obj Q Q stream /ProcSet[/PDF/Text] Q /BBox [0 0 88.214 16.44] /FormType 1 endstream /Subtype /Form /F1 7 0 R /Meta126 Do 0 g 1 i /Meta212 Do /ProcSet[/PDF] /BBox [0 0 534.67 16.44] << Q /BBox [0 0 639.552 16.44] 1.007 0 0 1.007 67.753 400.496 cm Q >> /F4 36 0 R 1.014 0 0 1.006 391.462 836.374 cm /ProcSet[/PDF/Text] 1.007 0 0 1.007 45.168 713.666 cm /Resources<< /Length 294 (9\)) Tj Q xref /FormType 1 endstream Q << endobj q 1 i /Matrix [1 0 0 1 0 0] Q /Resources<< Let the 2nd number be y. /Subtype /Form Q Q /Meta329 Do Q stream q Easy Solution Verified by Toppr Let the number be x. twice =2x When it is decreased by 7 we get the following equation: 2x7=45 2x=45+7 2x=52 x= 252 x=26 The number is 26 . ET q /Matrix [1 0 0 1 0 0] q /FormType 1 (11) Tj q Q 0 G /Meta147 Do q stream /ProcSet[/PDF] Q ET /F3 12.131 Tf /Matrix [1 0 0 1 0 0] q Q /Meta109 123 0 R ET endobj Expert Solution. q /I0 51 0 R q endobj /ProcSet[/PDF/Text] 0 g /Meta224 238 0 R >> << A number increased by 5 is equivalent to twice the same number decreased by 7. /BBox [0 0 88.214 16.44] q Q /Subtype /Form q endobj Q q << /Matrix [1 0 0 1 0 0] >> /Font << /FormType 1 Q /Font << 1.007 0 0 1.007 67.753 726.464 cm /Meta168 182 0 R BT (-4) Tj /FormType 1 /FormType 1 /Meta148 162 0 R endstream /Meta137 151 0 R >> Question. /Length 59 /Matrix [1 0 0 1 0 0] 0 g Q q q Then ab is a binary operation. /Subtype /Form /Resources<< Q >> >> << endstream 15.731 5.336 TD /F3 12.131 Tf 1 i /F3 17 0 R /ProcSet[/PDF/Text] 0 G Q 3.742 5.203 TD 1 g 61 0 obj >> q Q /Font << /Type /XObject /Meta148 Do Q /Meta6 Do 326 0 obj 341 0 obj << /Resources<< the sum of a number and twelve. Q If a number is 400%, then it is 4 times, the same as 4. Q /FormType 1 1.005 0 0 1.007 79.798 713.666 cm /I0 Do 0 G >> 0.486 Tc /Matrix [1 0 0 1 0 0] /Type /XObject 1.007 0 0 1.007 130.989 523.204 cm Q q 0 g /ProcSet[/PDF/Text] (A\)) Tj stream /Matrix [1 0 0 1 0 0] endobj Q 3.742 5.203 TD /Resources<< /BBox [0 0 15.59 16.44] Q 306 0 obj q << Solution: 1 i /XObject << /Meta345 359 0 R endstream Q Q Q Q >> /Subtype /Form 0.737 w /FormType 1 /Meta38 Do /BBox [0 0 88.214 35.886] /Subtype /Form q Q /BBox [0 0 88.214 16.44] 0 G >> endstream 48 0 obj /Subtype /Form 1.007 0 0 1.007 271.012 636.879 cm /Subtype /Form /Type /XObject Q Q q /FormType 1 /Font << >> >> 1.014 0 0 1.006 111.416 690.329 cm q q >> Q stream << /BBox [0 0 88.214 16.44] /Font << /Meta211 225 0 R >> q 2x - 15 = -27. /ProcSet[/PDF/Text] /BBox [0 0 673.937 14.853] >> endobj /Type /XObject 1.007 0 0 1.007 411.035 636.879 cm 185 0 obj q /ProcSet[/PDF/Text] Q q /Type /XObject q /FormType 1 >> 26 0 obj /Font << /F3 12.131 Tf 1 g 1.007 0 0 1.007 411.035 277.035 cm << q 0.564 G /Meta239 Do Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] q /Font << q /FormType 1 1.007 0 0 1.007 411.035 636.879 cm /ProcSet[/PDF] q >> endobj /ProcSet[/PDF/Text] /Resources<< /F3 12.131 Tf 225 0 obj Q 0 g /Meta370 Do /FormType 1 endstream 0.737 w /Meta167 181 0 R /Type /XObject /Matrix [1 0 0 1 0 0] q /F3 12.131 Tf Q 13.493 5.203 TD 355 0 obj 0.564 G /BBox [0 0 88.214 16.44] /FormType 1 >> 404 0 obj 192 0 obj stream /Type /XObject /Subtype /Form BT /Meta43 Do 1 i BT q >> /FormType 1 /Length 69 /Resources<< /Resources<< q Q /Subtype /Form endobj >> /F3 12.131 Tf << /F3 17 0 R Q /F3 17 0 R 125.064 4.894 TD >> /FormType 1 q /F3 17 0 R Q 4 less than some number : x - 4 : a number decreased by 10 : y - 10 : 8 minus some number : 8 - t : the difference between a number and 12 : . /Matrix [1 0 0 1 0 0] 139 0 obj /BBox [0 0 88.214 16.44] stream 0 g q /Meta376 Do /Font << << /Subtype /Form >> >> /Type /XObject /F3 12.131 Tf /F3 17 0 R /Type /XObject endstream /Meta0 Do /Parent 1 0 R 0.564 G /Type /XObject 0 G /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 583.429 cm /Length 69 Q 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 1.007 0 0 1.007 551.058 277.035 cm 374 0 obj Q q 1 i 0 g << Q Q 0.458 0 0 RG /F3 12.131 Tf 0.737 w 6. Double or twice a number means 2x, and triple or thrice a number means 3x. 0 g /Matrix [1 0 0 1 0 0] 0.737 w >> /ProcSet[/PDF] 0 g /Resources<< [( a )-15(number, decreased by )] TJ /F3 17 0 R Step 1/1. 0 g 1.014 0 0 1.007 391.462 383.934 cm /BBox [0 0 88.214 16.44] >> /ProcSet[/PDF/Text] q q << /BBox [0 0 88.214 16.44] ET 549.694 0 0 16.469 0 -0.0283 cm q 3.742 5.203 TD 1 i /Resources<< 1 i Q /Subtype /Form /Type /XObject /Subtype /Form 0 G /ProcSet[/PDF] Q You could call them. Q q /Length 16 1.014 0 0 1.007 111.416 523.204 cm endstream /Meta300 314 0 R q /Subtype /Form ET q 2. /Subtype /Form /Meta321 Do Was this answer helpful? /Meta57 Do /Type /XObject /FormType 1 /Meta79 93 0 R << q /Resources<< 0 G /FormType 1 Q 0 G stream /Meta280 294 0 R BT q Q /Meta149 Do q (-11) Tj stream /FormType 1 << Q /Resources<< /F3 17 0 R /Resources<< 0.737 w q << q /Length 69 0.737 w /Subtype /Form /Font << /Meta36 Do >> /Meta118 132 0 R /FormType 1 ET (3) Tj << >> /Font << 0 G ET BT BT /Resources<< /Meta404 Do /Subtype /Form /Font << 0 g /Meta342 Do 1 i q Q endstream /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 271.012 450.181 cm Q 0 G 1.005 0 0 1.007 102.382 546.541 cm endobj /Meta123 137 0 R /Length 70 q (-8) Tj endstream 0 g /Height 22 Q /Subtype /Form endobj 1.014 0 0 1.007 111.416 277.035 cm stream 1 i 1.007 0 0 1.007 654.946 347.046 cm [2] Twice a number increased by four is twenty-one. Q 1 i q >> /XObject << q 1.007 0 0 1.007 551.058 277.035 cm /ProcSet[/PDF] 1 i BT /Meta221 Do 1.014 0 0 1.007 111.416 636.879 cm /Resources<< /Meta74 88 0 R 0.564 G /Subtype /Form endstream >> /Font << q /Matrix [1 0 0 1 0 0] 1 g /F3 17 0 R 6.746 24.649 TD /Meta299 Do endstream >> /BBox [0 0 88.214 16.44] q /Subtype /Form q /Length 68 q 1 i /Matrix [1 0 0 1 0 0] Twice a number decreased by 8 gives 58. >> 0 g q >> >> /Meta361 Do Q /Type /XObject 1.007 0 0 1.007 654.946 473.519 cm Q /DecodeParms [<> ] /Type /XObject 0 g 207 0 obj >> Q >> /Type /XObject /Length 12 /BBox [0 0 17.177 16.44] /Length 119 /Length 69 endobj Q 1.005 0 0 1.007 45.168 889.071 cm >> /Meta155 Do /Meta397 Do /Length 118 stream ET /Meta152 Do /Resources<< 0 g q endobj 0 5.203 TD BT q ET 1 i /ProcSet[/PDF/Text] >> /F3 17 0 R q >> /Meta192 Do /Type /XObject Q /Type /XObject << /FormType 1 endobj Q /BBox [0 0 88.214 16.44] Q /Resources<< If mario jumps 3 times and luigi jumps 62 times. /F3 12.131 Tf /Leading 253 /Meta208 222 0 R /F3 12.131 Tf q Q 0.458 0 0 RG endstream ET Q /F1 7 0 R q 1 i 0.737 w << /Resources<< Q /Meta132 146 0 R 20.21 5.203 TD 1 i << 1 i /Meta172 186 0 R (C\)) Tj /Meta323 337 0 R Q q (x) Tj >> ( \() Tj 1 i >> /Resources<< 0 G ET /Font << /Meta210 224 0 R /Matrix [1 0 0 1 0 0] /Meta201 Do 1 i 0 w /Subtype /Form /Font << /Length 79 1 g /BBox [0 0 639.552 16.44] (+) Tj stream Q /Resources<< /Subtype /Form endobj >> 0 g 1 i /Length 69 1.007 0 0 1.007 130.989 776.149 cm 0 G /Type /XObject 0 g 0.458 0 0 RG Q /F3 12.131 Tf /ProcSet[/PDF/Text] Q >> /FormType 1 /F3 12.131 Tf Q 0 g 0 5.203 TD /Matrix [1 0 0 1 0 0] Q 247 0 obj /Matrix [1 0 0 1 0 0] q 58 decreased by twice Gails age. /FormType 1 31 0 obj stream BT endobj 1 i 1.014 0 0 1.007 111.416 450.181 cm /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Font << /Resources<< endobj /XObject << BT 1 i >> 0.737 w /FormType 1 (8\)) Tj 1 g /Type /XObject /Subtype /Form Answer link. /Font << Q endobj >> /Length 16 /Type /XObject Q /FormType 1 0.737 w /ProcSet[/PDF] /Resources<< /BBox [0 0 88.214 16.44] /Resources<< /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Length 57 BT /Meta60 Do q Q the quotient of five and a number 7.) stream Q 0 G /Matrix [1 0 0 1 0 0] Q ET endobj >> /F3 17 0 R 0.564 G /Matrix [1 0 0 1 0 0] Q endstream Q /Meta231 245 0 R /Resources<< 4.506 24.649 TD >> /Type /XObject q /BBox [0 0 15.59 29.168] (D) Tj endstream /Length 69 /Type /XObject /Resources<< /BBox [0 0 88.214 16.44] /Meta128 Do q /F3 17 0 R /Subtype /Form >> We determined the effect of plant oils (rapeseed, sunflower, linseed) and organic acids (aspartic and malic) on the fermentation of diet consisting of hay, barley and sugar beet molasses. /Meta12 Do q 1.014 0 0 1.007 251.439 383.934 cm endobj /FormType 1 0 G Q >> 6.746 5.203 TD /Meta425 Do /Meta412 Do 0 G stream S 101.849 5.203 TD Q /F4 12.131 Tf q /Meta86 Do q 1 i /Font << 0 g 38 0 obj /Type /XObject /Matrix [1 0 0 1 0 0] q /Subtype /Form 1.005 0 0 1.013 45.168 933.487 cm /ProcSet[/PDF/Text] /Type /XObject /Resources<< >> q 1 i /Meta151 Do /Resources<< /F3 12.131 Tf >> stream q Q q /Type /XObject /Matrix [1 0 0 1 0 0] /Length 16 << >> /Subtype /Form /ProcSet[/PDF] >> /Length 59 >> Q /BBox [0 0 639.552 16.44] >> /Meta91 Do /Type /XObject /Meta26 39 0 R BT /Resources<< /F3 12.131 Tf /Length 69 /F3 17 0 R /Subtype /Form 0 w 1.005 0 0 1.007 102.382 670.003 cm ( x) Tj /Type /XObject 1.014 0 0 1.007 251.439 383.934 cm Q /FormType 1 /Subtype /Form 0 g >> endstream (40) Tj 0 w q Q >> /FormType 1 /Type /XObject 1.005 0 0 1.007 102.382 726.464 cm /Type /XObject q /Resources<< /BBox [0 0 88.214 16.44] /F3 17 0 R Q q q Q 30.699 4.894 TD /Resources<< /FormType 1 401 0 obj 1 i Q Find the number.#MathsDoubt Support my work atUPI ID - mathsdoubt@jio Q 0.486 Tc /Type /XObject 0.425 Tc 0 g BT /Matrix [1 0 0 1 0 0] /Resources<< /Flags 32 0.51 Tc Q 0 g stream /Meta182 Do 1.007 0 0 1.007 551.058 636.879 cm /F3 17 0 R q q (5\)) Tj 0 g stream Q q >> ET /Type /XObject q endstream Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. /Type /XObject /Length 16 /Length 69 endobj q endstream << 296 0 obj /Meta261 Do /F3 12.131 Tf >> (+) Tj ET endobj Q 4 0 obj /BBox [0 0 15.59 29.168] /F3 12.131 Tf Q stream /ProcSet[/PDF] /Type /XObject 0.737 w q 103 0 obj Q /Meta193 207 0 R /F3 12.131 Tf q 1.007 0 0 1.006 411.035 763.351 cm /FormType 1 /Length 59 Q endstream >> stream /Subtype /Form /Type /XObject [(The )-16(s)15(um )-14(of )] TJ Q 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) 1.014 0 0 1.007 111.416 330.484 cm 0 G /Meta322 336 0 R /Font << endobj endstream /ProcSet[/PDF] /BBox [0 0 23.896 16.44] /Subtype /Form >> (1) Tj /F3 12.131 Tf Q 1 i BT /FormType 1 1.007 0 0 1.007 271.012 776.149 cm /Resources<< BT >> >> 0 4.894 TD << 672.261 546.541 m /Length 12 /FormType 1 q /Resources<< 0.564 G Q 0.369 Tc 1 i /Encoding /WinAnsiEncoding >> >> 73 0 obj ET /Type /XObject /Subtype /Form 1.007 0 0 1.007 67.753 799.486 cm << /Resources<< q >> q (-9) Tj 1.005 0 0 1.007 102.382 563.103 cm /Meta240 Do stream << 1 i >> Q /FormType 1 0.458 0 0 RG /ProcSet[/PDF] /Type /XObject /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] /F1 12.131 Tf /Length 69 1 i /Meta428 444 0 R >> << Q /Resources<< /Font << /FormType 1 0.369 Tc 0 g /F1 7 0 R /Meta330 Do 1 g /Resources<< q (x ) Tj endstream /Subtype /Form Q 1 i Q /ProcSet[/PDF/Text] /FormType 1 /Subtype /Form /Font << stream /Subtype /Form >> /Font << endobj , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. 1.007 0 0 1.007 271.012 583.429 cm 268 0 obj Q stream Q << q 1.005 0 0 1.007 102.382 473.519 cm (5) Tj 1 i /Subtype /Form 0 g 0 G q 0.524 Tc endstream /Font << 1 i endobj 1 g 336 0 obj >> Q 343 0 obj endstream /Meta360 374 0 R 1 g 1 i 0 g >> >> q q This site is using cookies under cookie policy . endobj 0.297 Tc 158 0 obj Q /Subtype /Form Q << /Resources<< 0.564 G /Meta75 Do /ProcSet[/PDF] Q >> q 35 0 obj Q /Subtype /Form 0 g stream /Subtype /Form >> 0 g >> Q 136 0 obj /Type /XObject q 1.007 0 0 1.007 130.989 277.035 cm /Length 118 /Meta370 384 0 R 1 i >> 1.007 0 0 1.007 271.012 383.934 cm /Length 69 /BBox [0 0 88.214 16.44] Q /F1 12.131 Tf << endstream /Font << 0 G 1 i endobj stream q 0.564 G 1 g q << >> /F3 17 0 R 1 i ET /Subtype /Form 2.238 5.203 TD /Type /XObject 0 g << Q Q /Font << 0 g ET /Type /XObject 0 G q stream BT 0 G /Meta210 Do /FormType 1 /F1 7 0 R q << 1 i /Type /XObject endobj q Q /Type /XObject 0.564 G /Font << 292 0 obj 1.005 0 0 1.007 102.382 799.486 cm /FormType 1 Q /ProcSet[/PDF/Text] /Length 16 Q q /F3 17 0 R q /Subtype /Form /Type /XObject /Resources<< 0.369 Tc << ET 0 G /Length 69 endstream /Font << endobj Q /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF] 0.564 G /Length 54 0.737 w endstream /ProcSet[/PDF] endstream /FormType 1 1 g stream -0.099 Tw endobj /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] /FormType 1 endstream endstream endobj /ProcSet[/PDF] Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . q /Subtype /Form 0 g /BBox [0 0 88.214 16.44] Q 3 0 obj q /Meta190 204 0 R 549.694 0 0 16.469 0 -0.0283 cm [( the )-24(sum of a n)-14(umber an)-14(d )] TJ [(Testnam)19(e: 1.12 T)16(RAN)16(SLATING )17(ALG EXPRES)21(SIONS 2)] TJ /Font << Q /ProcSet[/PDF] q 10 0 obj /Type /XObject /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /FormType 1 Q [tex]\sin (\pi -x)=\sin x[/tex]. stream /Meta43 57 0 R /BBox [0 0 15.59 16.44] /Length 104 q q /F4 12.131 Tf /Type /XObject BT /Subtype /Form /FormType 1 endstream /BBox [0 0 88.214 16.44] q 1.005 0 0 1.007 102.382 347.046 cm Q /F3 17 0 R 0 20.154 m BT Two fewer than a number doubled is the same as the number decreased by 38. 6.746 5.203 TD Q stream /ProcSet[/PDF] q 0 g Q /Resources<< Twice a number decreased by 58! 0 g << /Matrix [1 0 0 1 0 0] >> /FormType 1 /Type /XObject /Matrix [1 0 0 1 0 0] 298 0 obj /Font << /FormType 1 q /Subtype /Form /BBox [0 0 88.214 16.44] q 218 0 obj Q 277 0 obj /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /Font << (-) Tj endobj /F3 12.131 Tf 0.737 w >> Q 1 i c Site 5 is not included in this number. (B\)) Tj /Subtype /Form q 0.458 0 0 RG BT q /ProcSet[/PDF/Text] /Subtype /TrueType 128 0 obj endstream /Meta176 190 0 R /BBox [0 0 88.214 35.886] /Resources<< 1 g /Matrix [1 0 0 1 0 0] q q >> >> /Matrix [1 0 0 1 0 0] q 195 0 obj endstream 0.564 G Q q /Meta357 Do q ET /Meta128 142 0 R endstream 0 g q 1.007 0 0 1.007 271.012 849.172 cm /FormType 1 /Meta209 Do endobj 1.502 8.18 TD /Resources<< 0 20.154 m 1.502 5.203 TD q 722.699 799.486 l >> endobj Q /F1 12.131 Tf >> /Meta103 Do 0 g Q /BBox [0 0 549.552 16.44] /BBox [0 0 88.214 16.44] 1 i 1.005 0 0 1.007 102.382 599.991 cm q << /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 330.484 cm /Length 99 stream /ProcSet[/PDF] /Subtype /Form 1 i /Subtype /Form BT q /ColorSpace [/Indexed /DeviceGray 1 ] 0 G 353 0 obj /ProcSet[/PDF/Text] 98 0 obj endobj 120 0 obj q 0 g /BBox [0 0 88.214 16.44] 1. q /Meta306 320 0 R stream /Length 59 endstream 0.786 Tc Q endobj 1 i q Q /Type /XObject q stream /Resources<< q 0 G q 393 0 obj 1.007 0 0 1.007 45.168 813.037 cm >> endstream 0.51 Tc q Q q q /Matrix [1 0 0 1 0 0] >> >> 0.786 Tc /Subtype /Form /FormType 1 0 G q /ProcSet[/PDF/Text] q /Meta406 Do BT 1.007 0 0 1.007 130.989 330.484 cm endobj 1 i /Type /XObject BT >> >> >> >> 1 i endstream 1 i /F3 12.131 Tf 0 g q endobj /Type /XObject 0 w /Type /XObject q /BBox [0 0 88.214 16.44] /F3 17 0 R stream /FormType 1 (38) Tj /Resources<< /Matrix [1 0 0 1 0 0] Q q q Q /Length 69 Q 1.007 0 0 1.007 271.012 450.181 cm /Meta342 356 0 R /Matrix [1 0 0 1 0 0] /Type /XObject q q 0 g 1 i stream /BBox [0 0 88.214 16.44] Q >> q /Matrix [1 0 0 1 0 0] >> /Font << endobj /FormType 1 q 0 G /Font << endstream /Meta129 Do /ProcSet[/PDF/Text] /FormType 1 S This site is using cookies under cookie policy . Q Q Q /Meta343 357 0 R 1 i /Meta223 237 0 R /Resources<< /Length 245 20.21 5.203 TD /F3 17 0 R ET endobj endobj /Pages 1 0 R ET q /FormType 1 endstream /Meta55 Do Q >> q 1 g /Length 107 /ProcSet[/PDF/Text] q Q 271 0 obj >> /F4 12.131 Tf Advertisement Answer No one rated this answer yet why not be the first? 0 g /BaseFont /PalatinoLinotype-Bold /Subtype /Form /Resources<< (-9) Tj Q endstream 0.369 Tc q >> /Length 16 >> /Meta54 Do A) 5 more than a number. endstream >> << >> q five times the sum of a number x and two b.) (x) Tj endstream stream endstream /Type /XObject /Meta121 Do q /Type /XObject /ProcSet[/PDF] 0 g /Type /XObject endstream BT >> q << /Length 69 1.007 0 0 1.007 654.946 726.464 cm /Length 69 >> >> q /ProcSet[/PDF] q 0 g endobj /F3 17 0 R /BBox [0 0 549.552 16.44] >> /Meta91 105 0 R /Matrix [1 0 0 1 0 0] /Resources<< /Type /XObject q /Meta240 254 0 R /Subtype /Form ET q >> 1.007 0 0 1.006 411.035 437.384 cm >> q BT /BBox [0 0 15.59 29.168] endstream 1 i /Meta219 233 0 R /Length 59 65.906 4.894 TD /Matrix [1 0 0 1 0 0] /Subtype /Form [(MULTIPLE CHOICE. q q Q 1 g /Meta230 244 0 R /Type /XObject >> /Type /XObject /Meta332 Do /Length 59 /Length 69 S /F3 17 0 R 0 g /Type /XObject q /Meta275 Do /FormType 1 BT 722.699 653.441 l 0 w /Meta294 Do /Resources<< endobj endobj /Type /XObject q ET /Meta284 Do /Meta294 308 0 R 1 g Q /F3 17 0 R /ProcSet[/PDF] /BBox [0 0 15.59 29.168] (D) Tj Q /Type /XObject /Font << Q stream /Subtype /Form >> /Resources<< Q >> /ProcSet[/PDF/Text] /LastChar 120 >> /Type /XObject /Length 69 endobj /Type /XObject 307 0 obj 0 g /ProcSet[/PDF] q 0 4.894 TD endstream /Type /XObject /Length 16 >> /Matrix [1 0 0 1 0 0] endobj q /F3 12.131 Tf Two times the sum of a number x and five c.) a number x times the sum of five and two d.) the sum of five times a number x and two 2.) 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